What is the vertex of the graph of y = 3x2 + 2x + 1? A.-1/3, 0 B.-1/3, 2/3 C.1/3, 2 D.2/3, 11/3
y=3(0)^2 +2(0)+1 y=0+0+1 y=1
th vertex (turning point) is the point at which it reaches zero
no, it does not seem to be one of the options
the solution involves complex numbers, so there is no simple solution
When the parabola is given in the quadratic form, such as yours is: You can find the x coordinate of the vertex by using -b/(2a) For this particular parabola after plugging in the values of a and b, the x value is -2/2*3 or -1/3. So the vertex is at (-1/3 , y) Now it is only a matter of plugging in the x value in the original formula and solving for y to get the y value.
Solving for y, with x at -1/3 Y=3(-1/3)^2 + 2 (-1/3) + 1 y= 3/9 -2/3 + 1 y = 2/3 So the vertex is at (-1/3, 2/3) I do believe you may have an option that is satisfactory. @brittany8432
The vertex is the point where the parabola reaches its maximum or minimum depending on whether it is opening up or opening down. It may or may not occur when y = 0 or when x = 0
As in local max or min
Yes, y=3x^2 + 2x + 1 y'=6x + 2 set to 0 6x+2 = 0 6x=-2 x=-2/6 = -1/3 I did not know if the poster knew calculus. @BPDlkeme234
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