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Mathematics 12 Online
OpenStudy (anonymous):

Solve the equation

OpenStudy (anonymous):

what is it

OpenStudy (anonymous):

\[4=\sqrt{p}-2\]

OpenStudy (shinalcantara):

\[4 = \sqrt{p} - 2\] transpose -2 to the left. Combine first then square both sides

OpenStudy (shinalcantara):

\[4+2 = \sqrt{p}\]

OpenStudy (shinalcantara):

\[6 = \sqrt{p}\] or \[\sqrt{p} = 6\] square both sides just like what happened last time

OpenStudy (shinalcantara):

\[(\sqrt p)^2 = 6^2\]

OpenStudy (anonymous):

so you add 4=2 then square root

OpenStudy (anonymous):

opps 4+2

OpenStudy (shinalcantara):

yep. in the equation \[4 = \sqrt p - 2\] you will first transpose -2 to the left or in other terms, add 2 to both sides of the equation \[4 + 2 = \sqrt p -2 + 2\] \[6 = \sqrt p \] square both sides of the equation \[6^2 = (\sqrt p)^2\] \[p=?\]

OpenStudy (anonymous):

i want to say 36 but i feel worng

OpenStudy (anonymous):

its 36 i think

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