Question

Given the relation y = 3x^2 + 1, if the input is 4, what is the output?

13
48
49
145

Answer 1

@iGreen

Answer 2

y = 3x^2 + 1
f(4)=3(4)^2 + 1
f(4)= ?

Answer 3

....................................................

Answer 4

Input is x..so plug in 4 for x:

y = 3x^2 + 1

y = 3(4)^2 + 1

Simplify exponent:

y = 3(16) + 1

Multiply:

y = 48 + 1

Can you add that?

Answer 5

Yep ^^

Answer 6

Which point could be removed in order to make the relation a function?

{(–4, 3), (–5, 6), (1, 0), (–4, 5), (9, 5), (0, –7)}

(–5, 6)
(1, 0)
(–4, 5)
(9, 5)

Answer 7

@iGreen

Answer 8

Functions can't have two of the same x-value.

So which one can you take out?

Answer 9

A

Answer 10

is it a? o.o @iGreen

Answer 11

the answer?

Answer 12

No, are there two x-values with -5?

(1, 2)
^ x-value

Answer 13

There are two -4 x-values, so what's your answer gonna be?

Answer 14

c

Answer 15

Yep!

Answer 16

I g2g now..sorry.

Bye!

Answer 17

grr i need to give yah a medal >.<

Answer 18

Eh, doesn't really matter :P