Question

PLEASE HELP ME!!!
Write the equation of the line that is perpendicular to the line y = 2x + 2 and passes through the point (6, 3).

1. y = 2x + 6
2. y = -1/2x + 3
3. y = -1/2x + 6
4. y = 2x + 3

Answer 1

you line
y= 2x+2
is in the standard form of a straight line
y=mx + b

in the standard equation m is the gradient

so FIRST tell me what is the gradient of your line

y = 2 x + 2
y = m x + b (m= gradient)

Answer 2

So, 2 is the gradient

Answer 3

Yes well done 2 is the gradient

OK - I think that there is a mistake in your question, or how you posted it

none of the answers is correct.

Can you check what you posted please?

Answer 4

Yes, there was a problem in the way I posted it. I just fixed the answers, so hopefully they're correct now

Answer 5

a line which is perpendicular to the line

y= mx + b
has a gradient -1/m

in you case this would be -1/2

so the equation would be
\[y =\frac{ -1 }{ 2 }x +b\]

Answer 6

OK good so now you can see that 2 of your answers have a gradient of -1/2

Answer 7

So the answer would be y = -1/2x + 2?

Answer 8

no

Answer 9

Oh, so how do I get the correct value for b?

Answer 10

you know the equation is y = -1/2 x+ b

and you know that the point x=6, y=3 is on the line

SO

3 = -1/2 (6) + b

so work out what b is

Answer 11

Okay, I solved for b and ended up with 6. So the equation would be y = -1/2x + 6, which is #3. Correct?

Answer 12

well done - yes

Answer 13

Thanks so much, that was amazing help. I'm going to fan you and give you a medal :)