Ask your own question, for FREE!
Mathematics 12 Online
OpenStudy (anonymous):

Help me out? My answer doesn't seem to be correct?

OpenStudy (anonymous):

when I work it out I get: \[\sin^{2}a+\cos^{2}a\] But that isn't in the answer choices. I'm very confused.

OpenStudy (anonymous):

first off, without even looking, if it is \[\sin^2(x)+\cos^2(a)\] then it is \(1\)

OpenStudy (anonymous):

Yeah, that's what I was thinking--that it simplified into that fundamental identity, but apparently I've gone wrong somewhere.

OpenStudy (anonymous):

no you have not this question was written by a moron one of those other answers is 1 also we just have to figure out which one it is

jimthompson5910 (jim_thompson5910):

these identities may help http://www.regentsprep.org/regents/math/algtrig/att9/pythagoreanid.htm

OpenStudy (anonymous):

Thank you, you were right, sec^2a-tan^2a was equal to 1. It was just trying to trip me up. Thank you so much.

jimthompson5910 (jim_thompson5910):

yeah making something more complicated than it has to be, but they just want to make sure you're awake I guess

jimthompson5910 (jim_thompson5910):

choice D is correct

OpenStudy (anonymous):

yeah that is the right one but you could also pick \[\frac{2\times 3+5}{11}\]

OpenStudy (anonymous):

sometimes math teacher write amazingly dumb questions pity

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Latest Questions
willowjade: have to choose a movie to write an essay about. any suggestions?
9 hours ago 2 Replies 0 Medals
uknownprttyfacekayla: I wrote a story "a haunted love that was lost" let me know if I should add more.
53 minutes ago 19 Replies 7 Medals
Gucchi: pre calc help
1 day ago 8 Replies 0 Medals
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!