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OpenStudy (bizzeizzy):
what is the equation of the line perpendicular to the line y=2/3x+2 that passes through the point (1, 5)?
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OpenStudy (bizzeizzy):
\[y=\frac{ 2 }{ 3 }x+2\]
jimthompson5910 (jim_thompson5910):
what is the slope of that given line?
OpenStudy (bizzeizzy):
\[\frac{ 2 }{ 3 }\]
jimthompson5910 (jim_thompson5910):
flip the fraction: 2/3 ----> 3/2
flip the sign: 3/2 ----> -3/2
jimthompson5910 (jim_thompson5910):
the perpendicular slope is -3/2
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jimthompson5910 (jim_thompson5910):
the perpendicular line goes through (1,5)
(x,y) = (1,5)
x = 1
y = 5
jimthompson5910 (jim_thompson5910):
so we have this info
m = -3/2
x = 1
y = 5
you plug those values into y = mx+b and solve for b
jimthompson5910 (jim_thompson5910):
tell me what you get
OpenStudy (lunymoony):
b = 6?
OpenStudy (lunymoony):
i dont think this is right
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OpenStudy (lunymoony):
but Im out of my head tonight so Im not sure
OpenStudy (bizzeizzy):
so y-5=-3/2 (x-1)
OpenStudy (bizzeizzy):
right?
jimthompson5910 (jim_thompson5910):
now solve for y
OpenStudy (bizzeizzy):
y=1/2(13-3x)
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jimthompson5910 (jim_thompson5910):
that's another way of expressing
\[\Large y = -\frac{3}{2}x + \frac{13}{2}\]
jimthompson5910 (jim_thompson5910):
what I wrote is in slope intercept form
m = -3/2 is the slope
b = 13/2 is the y-intercept
OpenStudy (bizzeizzy):
ohh okay thank you for the help!
jimthompson5910 (jim_thompson5910):
you're welcome
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