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Mathematics 68 Online
OpenStudy (anonymous):

Given F(x) shown below, complete the equation for the inverse of F(x)

OpenStudy (anonymous):

OpenStudy (anonymous):

i am really struggleling with inverses. i would like for someone to explain in a easy way

OpenStudy (anonymous):

To find the inverse: Replace f(x) with y Switch x's and y's, so put x where y is and x where y is. Solve for y Replace y with f^-1(x)

OpenStudy (anonymous):

so replace f(x) with y then is gonna be y=35/5 +3?

OpenStudy (anonymous):

y=3x/5 +3 *

OpenStudy (anonymous):

Correct

OpenStudy (anonymous):

and switch x and y so x=3y/5 +3

OpenStudy (perl):

actualy your answer uses F^-1(y) = expression in y

OpenStudy (anonymous):

Ah, nice. Solve for x in this case :)

OpenStudy (perl):

y = 3x/5 + 3 , solve for x, that will be your 'inverse' function

OpenStudy (anonymous):

They made it even easier for you jackelyn :P

OpenStudy (anonymous):

So in this case you don't have to switch any variables around you can simply solve for x, and then let x = f(y).

OpenStudy (anonymous):

soo confusing i just ran to get some paper and a pencil to see how it goes. ok ok step by step

OpenStudy (anonymous):

f^-1(y)

OpenStudy (anonymous):

Ok since you're solving for f^-1(y), do this. Let f(x) = y No switching of variables. Solve for x. Let x = f^-1(y)

OpenStudy (anonymous):

ive always hated solving for things with fractions. so how can i solve for x here when i got a fraction

OpenStudy (anonymous):

so i tried it out and i believe its this. x=5(y-3)/3

OpenStudy (anonymous):

Shouldn't be in brackets

OpenStudy (anonymous):

Otherwise seems good :)

OpenStudy (anonymous):

\[x=\frac{ 5y-3 }{ 3 }\]

OpenStudy (anonymous):

You can simplify it a bit more, but you're fine now let x = f^-1(y)

OpenStudy (anonymous):

inverses dont like me :( i put the answer on apex and it said its (5/3)(y - 3) why?

OpenStudy (anonymous):

It's simplified as I was saying before, but since you put it in a computer, it doesn't understand it probably, but this is it. |dw:1416122964607:dw|

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