Simplify 1-sin^2x/cosx
HINT : \[\large \rm \sin^2x + \cos^2x = 1\]
I know that's an identity but I don't know how to get it like that
you do not want to change your question to look like the identity. you change the identity to look like your question
So I have 1-sin^2x = cos^2x now...
can i clarify something first?
is this the original equation? \[\frac{ 1-\sin(x)^2 }{ \cos(x) }\]
Yes
okay good
so what you just did was right!
now that you know that 1- sin(x)^2 is the same as cos(x)^2 what do you want to do? i see something similar in the equation!
It's similar to the sin^2x+cos^2x=1 identity?
wait wait!
remember when you said you got\[1-\sin(x)^2 = \cos(x)^2\]
Yes..what should I do after that?
where do you see\[1-\sin(x)^2\]
lets remember your original equation\[\frac{ 1-\sin(x)^2 }{ \cos(x) }\]
hint: you can replace something with the identity you have found, \(\cos^2 (x) = 1-\sin^2 (x)\)
I see 1-sin^2x on top
great! do substitution!
when you replace \(1-\sin^2 (x)\) with \(\cos^2 (x)\) what do you get?
Cosx?
yes :)
\[\frac{\cos^2(x)}{\cos(x)} = \cos(x) \implies \frac{x^2}{x} = x\]
Great! But the only thing I'm confused on is why we replaced 1-sin^2x with cos^2x
Because the identity whispered it into your ear and told you to do so.
Hahaha
Jk, we found he infamous identity \[\sin^2(x) +\cos^2(x) = 1\] and because we were already given \(\color{red}{1-\sin^2(x)}\) in our problem, we were able to use this identity to find out what it was equal to:\[\color{blue}{cos^2(x)} = \color{red}{1-sin^2(x)}\] so we just substituted it in. You can do that with identities, it's legit :P
Are you good? Do you understand? :o
Thanks! It's 1:36 AM here so I'm kinda on the struggle bus. But yeah you guys helped a lot! :)
Good luck :)
california i bet? same time here
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