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Mathematics 19 Online
OpenStudy (anonymous):

determine the measure of angle b of the triangle. the problem is attached in the post. help please

OpenStudy (anonymous):

OpenStudy (anonymous):

one moment, i have this problem worked out already. check my math please.

OpenStudy (jhannybean):

|dw:1416129796812:dw|

OpenStudy (jhannybean):

Alright :)

OpenStudy (anonymous):

OpenStudy (jhannybean):

Oh you're the one with the nice writing, I remember now.

OpenStudy (anonymous):

hehhe thanks, did you see the drawing i uploaded?

OpenStudy (jhannybean):

Yep.

OpenStudy (anonymous):

did you find an error in my math?

OpenStudy (jhannybean):

Checking

OpenStudy (jhannybean):

Yep

OpenStudy (wolf1728):

I calculate it as 28.858 degrees

OpenStudy (anonymous):

yup what?

OpenStudy (jhannybean):

theyre all correct.

OpenStudy (jhannybean):

@wolf1728 calculate `it`?

OpenStudy (anonymous):

yes please. i was under the impression to use law of cosine, then law of sins. then add both angles, subtract from 180

OpenStudy (wolf1728):

Using this calculator http://www.1728.org/trig4.htm (yeah, my website) :-)

OpenStudy (anonymous):

only problem, i cant use that on a test. i need to see how do this myself

OpenStudy (anonymous):

it doesnt even show steps. im not here for free answers, im here to learn

OpenStudy (wolf1728):

Heck, I'm willing to explain it too.

OpenStudy (anonymous):

can you work it out on paper and upload?

OpenStudy (anonymous):

did i use wrong approach to this problem on the work that i did and submitted?

OpenStudy (wolf1728):

Sure can - I'll work it out right here. I'm going by this page on my website: http://www.1728.org/trigtut2.htm Your problem involves 2 sides and an included angle - we need the law of cosines.

OpenStudy (wolf1728):

dabeezy - where are your calculations?

OpenStudy (anonymous):

i used law of cosines. did you look at the work i submitted?

OpenStudy (wolf1728):

Where is your work?

OpenStudy (anonymous):

attached at the top.

OpenStudy (wolf1728):

Okay I found it

OpenStudy (anonymous):

i found my mistake

OpenStudy (wolf1728):

side a^2 = b^2 + c^2 -(2*b*c *cos(A))

OpenStudy (anonymous):

its not 180=a+b+c. it is 180-c-a

OpenStudy (anonymous):

.....180-75 degrees-46 degrees=59 degrees

OpenStudy (wolf1728):

okay so you found the mistake! And you can go here: http://www.1728.org/trig4.htm to check your answers.

OpenStudy (anonymous):

thank you.

OpenStudy (wolf1728):

other side = 5.9617 angles = 28.858 and 105.14

OpenStudy (anonymous):

wait, thats what i had to begin with. both equations is the same thing. this still isnt correct

OpenStudy (anonymous):

other side = 5.9617 angles = 28.858 and 105.14 what?

OpenStudy (wolf1728):

That's what my calculation page says - maybe we should work it out

OpenStudy (anonymous):

those websites you upload is more confusing than how the book puts it. uploading websites isnt real help.

OpenStudy (wolf1728):

It's okay - I can work it our for you

OpenStudy (anonymous):

yes work it out is what ive been asking from the beginning. help=observing what i have,telling me where i went wrong.

OpenStudy (wolf1728):

Rather than looking over your work, why not just start at the beginning? side a^2 = b^2 + c^2 -(2*b*c *cos(A))

OpenStudy (anonymous):

if you observe my work, you would see that i have that on my paper worked out already

OpenStudy (wolf1728):

Yes, I know - but if I do it we both can see where you went wrong

OpenStudy (anonymous):

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