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PLEASE HELP ME ****need this to be 100% right please***
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ok
c
@anx @midhun.madhu1987 @Nurali
please, you have to use the subsequent inverse formula: \[C=\frac{ 5 }{9 }(F-32)\]
please, try to substitute your fahrenheit temperatures, and get the correspondent celsius temperatures
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for example: \[t _{1}=\frac{ 5 }{ 9 }(49-17)\approx 10\]
Sorry, an error is occurred! I retry: \[t _{1}=\frac{ 5 }{ 9 }(49-32) \approx 10\]
thanks
other temperature is: \[t _{2}=\frac{ 5 }{ 9 }(72-42) \approx 21\] so the difference is : 21-10=11
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