Question

Solve (w-8)^2-80=0 , where w is a real number.

Answer 1

?

Answer 2

kk I'm working it out for a sec I'll see if I can help okay @mathgirl2012

Answer 3

thanks ;)

Answer 4

http://www.algebra.com/algebra/homework/quadratic/Quadratic_Equations.faq.question.34172.html

See if this web page helps if does give medal

Answer 5

im sorry but that does not help me! :) @The_Jokers_wife

Answer 6

Try to expand \((w-8)^2\) then combine like terms. Then try to factor, or apply quadratic formula.

Answer 7

aww Okay well I don't know it than I'M SOOOOOO SORRY

Answer 8

is it \[w=\sqrt{80}+8\] ??

Answer 9

@geerky42

Answer 10

w^2 -16w + 64 -80 = 0

Answer 11

what??????

Answer 12

w^2 - 16w - 16 = 0

Answer 13

how???????

Answer 14

- i did what geerky suggested - expanded the binomial and combined like terms
now you have a quadratic to solve

Answer 15

im still a little confused????

Answer 16

(x - 8)^2 = (x - 8)(x - 8) = x^2 - 8x - 8x + 64 = x^2 - 16x + 64

Answer 17

oooohhhhhh

Answer 18

so the anwser is ^2 - 16w - 16 = 0

Answer 19

- replace x with w

Answer 20

no that's not the answer
you need to solve for w

to solve this equation you need to use the quadratic formula

Answer 21

\[w^2 - 16w - 16= 0\]
\[a= 1, b= -16, c= -16\]
\[x=16\frac{ 16\sqrt{256+64} }{ 2 }\]
\[x=\frac{ 16\pm \sqrt{320} }{ 2 }\]
Is that the anwser @cwrw238

Answer 22

@cwrw238

Answer 23

help!!!

Answer 24

HELP @cwrw238

Answer 25

PLEASE

Answer 26

HELP PLEASE

Answer 27

take the standard equation
a^2 + bx + c = 0
x = [ - b +/- sqrt(b^2 - 4ac)] / 2a

Answer 28

compare ur equation with the standard equation; a = 1, b = -16 and c = -16
so replace a , b and c with 1,-16 and -16 in the formula and work it out

Answer 29

I DID

Answer 30

i'll start it off for you - nite the + or - I'll do the + one
w = [-(-16) + sqrt( -16^2 - 4 *1*-16)] / 2

Answer 31

* i meant note not nite!!

Answer 32

you did - good

Answer 33

can you tell me if I did it right

Answer 34

what answers did you get?

Answer 35

\[x=\frac{ 16\pm \sqrt{320} }{ 2 }\]

Answer 36

\[x=\frac{ 16\pm 8\sqrt{5} }{ 2 }\]

Answer 37

??????????????

Answer 38

divide by 2

Answer 39

following on
w = (16 + sqrt 320) / 2
= (16 + 17.888) / 2 = 16.94

Answer 40

@mathgirl2012 (w-8)^2-80=0 are you doing this one ???

Answer 41

the other root is ( 16 - 17.888) / 2

Answer 42

YES I AM @Nnesha

Answer 43

8

Answer 44

divide 16 and 8 by 2

Answer 45

\[\frac{ 2\pm \sqrt{5} }{ 2}\]

Answer 46

oh - so they want the answer in surd form?

Answer 47

when you divide by 2
now divide 8 by 2