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Differential Equations
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Use laplace transform to find the answer to the initial value problem y''-2y'+5y=0, y(0)=2 y'(0)=4. PLEASE HELP!!!
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:D We just did this
ok so, first step, laplace trans of both sides, can you write that out?
i figured it out, i got to the point where i had Y(s)=\[ \frac{ 2s }{ s^2-2s+5 }\] and i realized i had to change the numerator to 2(s-1)+2 and inverse laplace transform from there. Thanks though!
ah ok np!
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