What is the probability that a randomly chosen person is female or likes McDonalds?
@kropot72
Man, I was having trouble on this question, and when I saw you online, you made my day :D
I don't know where to start on this one, its complicating. I know when its "or" I have to find the sum. But it still won't give me the answer.
Have you completed the table by finding the sums of the rows and the columns? This is the first step.
Yes, I know the sum of the whole table is 100, and I know that for females is 55, and that for mcdonald is 40
Good. So we know the following: P(F) = 0.55 P(McD) = 0.4 Now you need to find the intersection of 'female' and 'likes McDonalds' on the table.
.55/100 + .40/100 (
So far so good. Now you need to find the intersection of 'female' and 'likes McDonalds' on the table.
And I have to subtract them by p(female and from mcdonald) Which I think is .20/100
Is that it, because in my book, it says the answer is 3/4, and I don't know how they came up with this answer
The formula needed is: \[\large P(A \cup B)=P(A)+P(B)-P(A \cap B)\]
I'm familiar with this formula, but is p(female and from mcdonald)=.20/100 right? I just want to make sure
\[\large P(Female\ \cap McDonalds)=\frac{20}{100}=0.2\]
Yeah, got it, I accidentally placed the decimals and it kept giving me the wrong answer.
Thanks bud :D
You're welcome :)
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