Question

Differentiate y=−2tan(cosx).

Answer 1

Have you tried the chain rule?

Answer 2

-2 is a constant so you can just leave it as it is

Answer 3

would it be -2(tan)(-sinx) ?

Answer 4

close
what is the derivative of tan(x)

Answer 5

ah so the n-2tan(sinx)+sec^2x

Answer 6

chain rule is derivative of outside(inside stays same here) * derivative of inside

Answer 7

Myininaya :D

Answer 8

-2sec^2(-sinx)?

Answer 9

\[y'=\frac{d}{dx}[-2 \tan(\cos(x))]=-2 \frac{d}{dx}\tan(\cos(x)) \\ =-2 \cdot \frac{d}{dx} \tan(x)|_{\cos(x)} \cdot \frac{d}{dx}\cos(x)\]

Answer 10

oh wait -2sec^2(cosx)?

Answer 11

*the derivative of the inside
you almost have it

Answer 12

-2sec^2(cosx)(-sinx)?

Answer 13

That looks good! You can simplify it a bit more :)

Answer 14

yes as ugly as it is
and - * -

Answer 15

im so bad at math ;;

Answer 16

do you see what batman was saying you can simplify ?

Answer 17

the cos and the sec?

Answer 18

(2sinx)/(cosx)?

Answer 19

no