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Mathematics 16 Online
OpenStudy (anonymous):

Another volume question need help figuring out!

OpenStudy (fibonaccichick666):

on this one, you want to set up a proportion

OpenStudy (fibonaccichick666):

two fractions that are equal to each other

OpenStudy (anonymous):

I'm not sure how to do that... I don't set the two volumes up as a fraction?

OpenStudy (fibonaccichick666):

yes, actually, make a fraction of the two volumes, then set that equal to the areas, make sure you keep the big on top for both or vice versa

OpenStudy (anonymous):

so like 512 mm^3/ 343 mm^ 3 = 192 mm^2/ v2 ... I think?

OpenStudy (fibonaccichick666):

yep, then solve for what you called v

OpenStudy (anonymous):

How do I solve for that? divide the 512 and 343? I don't have an exponent on my calculator.

OpenStudy (fibonaccichick666):

no, and you don't need exponents. so, the trick with proportions is to use something called cross multiplying check it out here: https://www.khanacademy.org/math/cc-seventh-grade-math/cc-7th-ratio-proportion/cc-7th-constructing-proportions/v/find-an-unknown-in-a-proportion

OpenStudy (anonymous):

wait I think I do 192 * 512/342 (2/3)

OpenStudy (anonymous):

I don't know...

OpenStudy (fibonaccichick666):

you have \[\frac{512}{343}=\frac{192}{x}\] Solve for x

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