Question

Pythagorean triple help? will medal

Answer 1

http://www.mathsisfun.com/pythagorean_triples.html

Answer 2

\[(x^2+y^2)^2=(x^2-y^2)^2+(2xy)^2\]

Answer 3

use this to figure out the triples

Answer 4

x=8 y=1

Answer 5

hint #1 \[c^2=a^2+b^2\]

Answer 6

@jim_thompson5910

Answer 7

?

Answer 8

you can always just post a quick screenshot of the material, use the [Attach File] blue button

Answer 9

not sure what you need ... i posted a link to huge list of examples of pythagorean triples

Answer 10

Use the Polynomial Identity below to help you create a list of 10 Pythagorean Triples:

Hint #1:
Hint #2: pick 2 positive integers x and y, where x > y

Answer 11

ok

Answer 12

its page 3 of 6

Answer 13

i chose x=8 and y=1

Answer 14

oh i see, yeah ok you can plug in x and y into that equation you posted to get a triple as well

Answer 15

@jdoe0001

Answer 16

ok

Answer 17

for x=7 y=3 my triples are (40,42,58)

Answer 18

correct

Answer 19

ok but then i got stuck when i picked x=8 and y=1 lol

Answer 20

8^2 + 1^2 = 65

8^2 - 1^2 = 63

2(8)(1) = 16

Answer 21

ohhhhh lol

Answer 22

so then if x=9 and y=1 then it would be (18,80,82)?

Answer 23

yes

Answer 24

._. maybe i should be named dumbcow lol

Answer 25

haha :)

Answer 26

ok and lastly if you open the file again the last page is the hardest. i need help with the far right problems

Answer 27

this isnt that hard, notice how they just replace the number with "y"

so using the formula on the right, plug back in the number for "y"

Answer 28

wait what? lol, ohh so where its like this

\[(x+2)^2=(x+y)^2+x^2+2xy+y^2\]

Answer 29

then plug in 2 where y is?

Answer 30

yeah ----> x^2 +4x +4