@e.mccormick which angle is theta?
Theta is, by definition of the unit circle, from the (0,1) coordinate swung over to the point. However, you can use the reference angle inside the circle to find the values if you want nd then the +- rules for quad 2 to make sure you have the correct answer.
I'm confused...
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Reference angles are always < 90.
oh...so how do i find sec theta if it isn't even in the triangle?
However, you can use the x,y coordinate definitions. For a radius of r: \(\sin=\dfrac{y}{r}\) \(\cos=\dfrac{x}{r}\) If it was a unit circle, r would be 1. But this is some line, so you need to find r first. r for radius, which is also h for hypotenuse. So, distance formula!
i think i found the answer...4.123
Or adapt thr Pythagorean Formula for Hypotenuse... same thing.... Hmm... I did not do the math. \((-1)^2+4^2=17\) \(\sqrt{17}\approx 4.123\) So that is r or the hypotenuse.
The secent is the inverse of cos, so \(\dfrac{r}{x}\) and since x is -1, your answer is off a bit.
\(\dfrac{\sqrt{17}}{-1}\) Do you see the problem with your answer?
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thanks. i do see. :)
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