Question

Of 6000 apples harvested, every third apple was too small, every fourth apple was too green, and every tenth apple was bruised. The remaining apples were perfect. How many perfect apples were harvested?

@PaulaLovesSchool13

Answer 1

So the third was bruised, the fourth was too green, and the tenth was bruised. So if you get a least common factor it would be every 60 apples because 3, 4, and 10 all fit into 60. This means that 60 is dividable by all of these numbers 3, 4, or 10.

Every third of 60 is 60/3 = 20 apples, every 4th is 60/4 = 15 apples, but remember that some apples are both too small and too green. That means that every 1 out of 12 are both small and too green, so get 1/12 of 60 and subtract that number from the 15. The reason you use 12 is because 3 and 4 both fit into 12 as in if you multiply them.

So every third apple is 20 + every fourth is 15 minus 5 apples, because you don't count the same apple again equals 30 apples. So 30 apples includes the too small and too green apples. But we're still not done yet.

Now count the every 10th apple, but again don't count the same apples. 1/10 of 60 is 6 apples, but if you find the least common factor of 3 and 10 or 4 and 10 you get 20, 30, 40, and 60. So don't count 4 apples. That means for every apple that is bruised and only bruised is another 2 apples.

Now add 2 to that 30 apples to get 32 apples. So 32/60 every 60 apples are bad. Or you can multiple these numbers by 100 to get 3200 out of every 6000 apples are bad. Leaving 2800 good apples.

Answer 2

Is there a way to find out "What if n apples were harvested?"