MEDAL! Suppose a parabola has an axis of symmetry at x = –7 , a maximum height of 4 and also passes through the point (–6, 0). Write the equation of the parabola in vertex form. Show all work

Question

MEDAL! Suppose a parabola has an axis of symmetry at x = –7  , a maximum height of 4 and also passes through the point (–6, 0). Write the equation of the parabola in vertex form. Show all work

studygurl14 · Answer

Hi @mikaylabean

anonymous · Answer

x=-7 symmetry, and the point is (-6,0) sorry about that.

anonymous · Answer

Hey! @StudyGurl14 Can you help me out? (:

studygurl14 · Answer

Yep. :)

anonymous · Answer

Awesome!!

studygurl14 · Answer

Vertex Form of a Parabola:
$\large y=a(x-h)^2+k$

where $\large(h,k)$ is the vertex

anonymous · Answer

Okay.. So I Know -7 will be the H of the vertex..right?

studygurl14 · Answer

Since this parabola has a "maximum height", we know that it must open downward. This indicates the graph is negative, and thus, a= -1

anonymous · Answer

Okay. Got it! Wouldn't the max height effect the vertex?

studygurl14 · Answer

I have to go eat lunch. View this: http://www.mathwarehouse.com/geometry/parabola/standard-and-vertex-form.php And use https://www.desmos.com/calculator to check your answer

studygurl14 · Answer

@mikaylabean sort of. The maximum height of 4 indicates that the highest y-value possible for this parabola is 4

anonymous · Answer

Okay!!! I'll post my answer, maybe you could check it also!

studygurl14 · Answer

okay. is it ok if i check later. gtg bye