Given the parent function of f(x) = x4, what change will occur when the function is changed to -f(2x)? @jim_thompson5910
graph y = x^4 using desmos
then add on -x^4 for the second row and finally, add on -(2x)^4 for the third row
hopefully you see how the graph is changing
Oh okay thank you so much. I'll let you check my answer later
alright
Graph opens the opposite way and is narrower?
@jim_thompson5910
very good
thanks!
What is the end behavior of the function f(x) = -x3 + 2x2 + 4x + 5? Up on the left, up on the right Up on the left, down on the right <----- MY ANSWER Down on the left, up on the right Down on the left, down on the right Is it right? @jim_thompson5910
correct
What are the coordinates of the turning point for the function f(x) = (x + 3)3 + 1? How would I do this one? @jim_thompson5910
the turning point of y = x^3 is (0,0) graph both y = x^3 and y = (x+3)^3 + 1 in desmos and notice how the shifts occur
hopefully you see the turning point?
in different rows right? @jim_thompson5910
yes each row is a separate equation/graph
it says the turning point for x^3 is (0, 0) then for (x+3)^3 it changes to (-3, 0) but that isn't any of my answer choices.
@jim_thompson5910
now shift things up 1 unit
you forgot about the +1 at the end
ohhh so (-3, 1)?
@jim_thompson5910
you nailed it
Thank you!! I'll keep doing this but I'll definitely need your help, so it would be great if you just keep an eye out for my questions and help me out if you don't mind :)
What polynomial identity should be used to prove that 133 = 125 + 8? Difference of Cubes Difference of Squares Square of Binomial Sum of Cubes <----- MY ANSWER @jim_thompson5910
@jim_thompson5910 is that right?
yes because 125 = 5^3 and 8 = 2^3 125 + 8 = 5^3 = 2^3 = sum of cubes
yep! :D
Use the graph of the function f(x) = x3 - 3x2 - x + 3 to answer this question: graph of x cubed minus 3 x squared minus x plus 3 What is the average rate of change from x = -1 to x = 2? -3 -1 <----- MY ANSWER 0 3 What about this one?
it is correct
Another one i can't seem to figure out it's very confusing @jim_thompson5910
Select the graph and the description of the end behavior of f(x) = -x3 - 2. graph that decreases from left to right that passes through ordered pairs negative 2, 10; negative 1, 3; 0, 2; 1, 1; and 2, negative 6 This is a cubic function. The end behavior of the graph will decrease to the right and increase to the left. graph that increases from left to right that passes through ordered pairs negative 2, negative 6; negative 1, 1; 0, 2; 1, 3; and 2, 10 This is a cubic function. The end behavior of the graph will increase to the right and decrease to the left. graph that increases from left to right that passes through ordered pairs negative 2, negative 10; negative 1, negative 3; 0, negative 2; 1, negative 1; and 2, 6 This is a cubic function. The end behavior of the graph will increase to the right and decrease to the left. graph that decreases from left to right that passes through ordered pairs negative 2, 6; negative 1, negative 1; 0, negative 2; 1, negative 3; and 2, negative 10 This is a cubic function. The end behavior of the graph will decrease to the right and increase to the left.
yikes...giant wall of text lol
LOL sorry I'll try to graph them if u would like?
it's fine lol, but graphing -x^3 - 2 should help you find the answer
oh okay let me try that out
to find ordered pairs on the graph, you can also set up a table
I got D as the answer @jim_thompson5910
how many answer choices are there?
A through D
ok
choice D says graph that decreases from left to right that passes through ordered pairs negative 2, 6; negative 1, negative 1; 0, negative 2; 1, negative 3; and 2, negative 10 This is a cubic function. The end behavior of the graph will decrease to the right and increase to the left. right?
not sure where it starts
yeah ur right but I graphed it on desmos and it looked the same as my answer choice @jim_thompson5910
ok let me graph real quick
ok
yeah it decreases and it goes through (0,-2)
alright! another one lol I am extremely sorry
What are the possible numbers of positive, negative, and complex zeros of f(x) = -3x4 + 5x3 - x2 + 8x + 4? Positive: 2 or 0; negative: 2 or 0; complex: 4 or 2 or 0 Positive: 1; negative: 3 or 1; complex: 2 or 0 Positive: 3 or 1; negative: 1; complex: 2 or 0 Positive: 4 or 2 or 0; negative: 2 or 0; complex: 4 or 2 or 0
@jim_thompson5910
is it B? @jim_thompson5910
how many sign changes are there in -3x^4+5x^3-x^2+8x+4
2
I count 3 sign changes from -3x^4 to +5x^3 from +5x^3 to -x^2 from -x^2 to +8x
oh yeah sorry my bad lol ur right
so there are at most 3 positive real roots
now we need to find f(-x) f(x) = -3x^4+5x^3-x^2+8x+4 f(-x) = -3(-x)^4+5(-x)^3-(-x)^2+8(-x)+4 f(-x) = -3x^4-5x^3-x^2-8x+4 how many sign changes are there in f(-x) ?
2? @jim_thompson5910
just one this time: -8x to +4
so there is at most 1 negative real root
now let's say we had 3 positive real roots that leaves 1 root left over, so we'd have 1 negative real root because complex roots always come in pairs
if we had 2 positive real roots, then we'd have 2 complex roots as well
one sec, reading something on the descartes rule of signs
okayy
ok according to this http://www.purplemath.com/modules/drofsign.htm we subtract by 2
so we'll have 3 or 1 positive root
Thanks @jim_thompson5910
Use the graph of the function f(x) = 3x4 - x3 + 3x2 + x - 3 to answer this question: graph of 3 x to the fourth, minus x cubed, plus 3 x squared, plus x minus 3 What is the average rate of change from x = -1 to x = 0? -6 -3 3 6 I'm stuck on this.. @jim_thompson5910
you need to evaluate \[\Large \frac{f(-1)-f(0)}{-1-0}\]
idk what to do @jim_thompson5910
Can u tell me what to do? @jim_thompson5910
do you know what f(-1) means or represents?
y?
is the answer 3? @jim_thompson5910
f(-1) is the y value when x = -1
to find f(-1) you plug x = -1 into the function f(x) and evaluate
what is f(-1) equal to?
I got 3
@jim_thompson5910
f(0) = ???
i thought u said f(-1)??
yes sorry, I want to know both f(-1) and f(0) f(-1) = 3 is correct now what is f(0) equal to
0?
nope
plug x = 0 into the function and evaluate
i did and i got 0 somehow
try it again, you should get -3
-3 isn't the answer btw, it's just the value of f(0)
oh yeah i got -3 sorry for 3*0^2 I somehow got 3 instead of 0 i wasnt thinking lol
I see
f(-1) = 3 f(0) = -3 \[\Large \frac{f(-1)-f(0)}{-1-0} = \frac{3-(-3)}{-1-0} = ???\]
-6
@jim_thompson5910
-6 is the ultimate answer
correct
Thank you sooo much!!! how can u make something seem SOOO easy seriously u make me feel dumb all the time LOL @jim_thompson5910
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