Question

If a 375 mL sample of water was cooled from 37.5 C to 0 C how much heat wad lost in joules

Answer 1

please, you have to apply the formula below:
\[Q=c*m*\Delta t\]
where Q is the energy lost,
c is the specific heat of water,
m is the mass of water involved,
so m=3.75 *10^-1 Kg
c=4,184 J/(Kg*°C)
delta t=37.5 °C

Answer 2

Taking density of water as 1000kg/m3. Mass of water would be 0.375kg. So, heat lost would be \[H=mC DeltaT\]
H=0.375*4184*37.5 = 58837.5J

Answer 3

please, you have to perform the calculation using the above data