Tan(t)= -1 should be easy for ya =(
Do you want to know how to solve for \(t\)?
it says, Solve the following equations in the interval [0, 2 pi].
if u can show me and it wouldn't take alot of time i would gladly appreciate it wio
First of all, do you understand the unit circle?
mmm unit circle is r=sqrt(x^2+y^2 ?
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holy pellet did u just draw that
The unit circle is a circle whose radius is \(1\) and it centered at the origin \((0,0)\).
yes yes x being cos and y being sin
Alright, well \[ \tan(t) = \frac{\sin (t)}{\cos(t)} \]
In our case, we would say: \[ \frac{\sin t}{\cos t} = -1 \implies \sin t = -\cos t \]
oh yes i remember that go on
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|dw:1416511579409:dw| At the \(45^\circ\) angles, we can see that \(x\) and \(y\) coordinates on the unit circle will be roughly equal. And also, \(45^\circ =\pi/4\)
is negative 1 = sin/cos a rule?
it's only the second and first quadrants, though, where you have \(y=-x\).
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