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Find all the zeroes of the equation. -3x4+27x2+1200=0 I need to learn how to do it! Just not the answer please
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finding the zeroes is the same as solving for X order of operations first multiplication -3*4=-12, 27*2=54 -12+54+1200=0 now add everything else together The answer would be 1242
I think 4 and 2 are exponents on x
\[-3x^4+27x^2+1200=0\]
try replacing x^2 with u to transform the equation into: \[-3u^2+27u+1200=0\]
this is a quadratic equation
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use the quadratic formula
you could also simplify the equation before using the formula
divide both sides by -3
Yeah the 4 and 2 are exponents
oh, oops, sorry >.<
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Nah you're good! thanks for the help though :)
oh wait never mind, I got it.
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