A block of mass m1 = 3.50 kg on a frictionless inclined plane of angle 30.0° is connected by a cord over a massless, frictionless pulley to a second block of mass m2 = 2.60 kg hanging vertically (Fig. 5-54).

Question

surry99 · Answer

Sketch or post the diagram and I can help you.

anonymous · Answer

http://www.webassign.net/hrw/05_52.gif

surry99 · Answer

ok, now what are they asking you to solve for?

anonymous · Answer

i figured out the accelleration is 1.37 but i can't figure out the tension in the rope

surry99 · Answer

Does the acceleration occur down the ramp?

anonymous · Answer

no up the ramp

surry99 · Answer

ok i have not checked to see if that is correct but to get the tension in the rope, draw a FBD of mass 2 assuming it it accelerating down. Go ahead

anonymous · Answer

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anonymous · Answer

?

surry99 · Answer

Let me help...hang on

surry99 · Answer

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surry99 · Answer

Now, you can see the mass.
What is the force acting down?
What is the force acting up?

surry99 · Answer

Try to label the vectors

anonymous · Answer

force acting down is gravity, force acting up is the other block??? idrk

surry99 · Answer

The force acting up is the tension in the rope my friend

anonymous · Answer

hahaha oh

surry99 · Answer

Now can you write the equation that relates m2, g, T and a?

anonymous · Answer

T=m2g(a) ????

anonymous · Answer

maybe

surry99 · Answer

not quite...hang on

anonymous · Answer

hahahaha, i havent been in class for a few days so

surry99 · Answer

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