write y=(-3/4)x+3 in standard form using integers. Please help:D will fan and medal
to start things off, you can multiply both sides by the LCD 4 to get y=(-3/4)x+3 4*y=4*[(-3/4)x+3] 4y = 4*(-3/4)*x + 4*3 4y = (-12/4)x + 12 4y = -3x + 12 Notice how the fraction went away
now you need to get the equation into the form Ax+By = C
how do i do that?
A,B,C are just fixed numbers for example, 2x+3y = 7 is in Ax+By = C form where A = 2, B = 3, C = 7
how would you change 4y = -3x + 12 to get it into the form Ax+By = C? or put another way, how would you change 4y = -3x + 12 so that it looks like 2x+3y = 7
-3x+4y=12?
you can't just move the -3x over like that
you have to do something to both sides to move it over
What do i have to move? i have so many rules mixed up in my head i cant think of how to do anything rn.
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