Solve the equation 3x^3-22x^2+29x+30=0 given that zero 3 is a zero of 3x^3-22x^2+29x+30=0

Question

loser66 · Answer

what is "zero 3" ?

anonymous · Answer

Yes

loser66 · Answer

Does it mean 3 is one of the zero?

anonymous · Answer

Yes

anonymous · Answer

Zero 3 is a zero of? i'm guessing you mean "given the zero of 3" or "3 is a zero of the function"

Your first step would be to factor out (x-3)

loser66 · Answer

if it is so, then you can break the expression into parts by take long division.
That is $\dfrac{3x^3-22x^2+29x+30}{x-3}$

anonymous · Answer

ugh
what is wrong with synthetic division?

anonymous · Answer

$$(x-3)(3x^2+bc-10)$$ even 
then find $b$

loser66 · Answer

:) nothing is wrong, just the same, right? but I prefer long division.

anonymous · Answer

Yeah I did synthetic division I got 3x^2-13x-10

anonymous · Answer

i prefer the think method 
$$(x-3)(3x^2+bx-10)$$ the 3 and the -10 are obvious, all that is left is to find $b$

anonymous · Answer

ok then you have a quadratic, you can always find the zeros of a quadratic