Can someone help me. I need help.
Write a polynomial function of the nth degree that has the given real or complex roots.
n=3; x= -2, x=3i

Question

Can someone help me.  I need help.
Write a polynomial function of the nth degree that has the given real or complex roots.  
n=3; x= -2, x=3i

anonymous · Answer

Please I will give a medal!!!

anonymous · Answer

help me please

fibonaccichick666 · Answer

so first what can you write down for a zero at x=2?

anonymous · Answer

The zero is 2
I think I got it is this correct?
x^3 - x^2-6x-3ix^2+3ix + 18i

fibonaccichick666 · Answer

uh... you should leave it un-muiltiplied out

campbell_st · Answer

an easy way to look at this problem is start with the complex roots. 

you have 

$$x = \pm 3i$$

if you square both sides of the equation you get

$$x^2 = 9i^2$$

and you should know 

$$i^2 = -1$$

so then 

$$x^2 = -9$$

which can be written as a quadratic factor of 

$$(x^2 + 9) = 0$$

you linear factor comes from 

x = -2  is a zero so   x + 2 is a factor 

combining the factors gives

$$(x + 2)(x^2 + 9) = 0$$

your task is to now expand to get the cubic