What is the slope of a line perpendicular to the line with equation y = 6x + 2?
A.6 B.-6 C.3 D.- 1/6
If you know the slope of the first line, then what do you automatically know about the slope of a line perpendicular to it? Use that property to compute the slope of the second line.
-6x + y = 4 you can move the variables around to get the form: y = mx + b, which is the slope intercept form. y = 6x + 4 here: m = 6, b = 4 m is the slope of the line, so slope is 6 any line parallel to this line will also have the slope of 6 any line perpendicular to the given line will have the slope of: -1/m1 we know m1 = 6, so the perpendicular line will have the slope of: -1/6
1 sec
There you go
So B is your ansswer
the answer is not B
if you have a line y = mx + b the slope of the line is m the perpendicular line has a slope \[m_{perpedicular} = \frac{-1}{m}\] the product of the 2 slopes \[m \times m_{perpendicular} = -1\] so find the slope of your line.. and then find the negative reciprocal
thx
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