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use L'Hospital Rule. lim x->0+ (tan5x)^x
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What do you need to use Mr. L'hops?
\[(\tan 5x)^x = e^{\ln (\tan 5x)^x} = e^{x \ln(\tan 5x)}\] now apply the limit as x->0
would the limit be 1?
Thank you so much.
yw yes lim = 1
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but that's not using l'hopital?
is it required to use L'Hopitals rule?
no, if a more elementary way can be used than...
it said so
yes
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so, since we have to use L'hops, what do we need to use it?
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