Question

please need help

Answer 1

here is the problem

Answer 2

First find the slant height (you can do this since you know the height, and the length of one side of the base) then you can sue this to find the area of a side.

Start by identifying the slant height on the diagram, and deciding how you will find that length.

Answer 3

can you solve it so i can see how you do it?

Answer 4

Sure. It's kind of long, just hold for a bit.

Answer 5

thx

Answer 6

First I'm going to label the diagram so we know what we're talking about:

Answer 7

To find the area of side ABC we need two things: side BC, and the slant height, AE.

We already know BC, its given as 2.

To find AE we can use Pythagoras: \[AD^{2}+DE^{2} = AE^{2}\] OR \[AE = \sqrt{AD^{2} + DE^{2}}\]

Good so far?

Answer 8

yes

Answer 9

DE is 1 (1/2 the base)

Plug in what we know: \[AE = \sqrt{3^{2}+1^{2}}\]\[AE = \sqrt{9+1}\]\[AE=\sqrt{10}\]

Now we can find the area of ABC:
\[area= \frac{base \times hegiht}{2}\]\[area=\frac{BC \times AE}{2}\]

Answer 10

Again plug in what we know: \[area = \frac{2 \times \sqrt{10}}{2}\] and simplify \[area = \sqrt{10}\]

Answer 11

Thanks alot :)

Answer 12

No problem.

Answer 13

can you help me with one more?

Answer 14

Sure

Answer 15

Ok. So basically we have 2 long sides, 2 short sides and 2 triangles (no paint on the roof). We need to find the area of all of that added up, then double it (2 coats of paint) and divide the total by 250 gal/sqft.

Answer 16

If we could "un-fold" the building it would look like this (ignoring the roof) That's the area we need to find.

(crappy drawing but you get the idea)