Question

HELP PLEASE:)

Answer 1

Find an equation of the tangent line to the graph of the function at the point (9, 1).
y = 6x − 9

Answer 2

:( SOMEONE?

Answer 3

first, you need to find the derivative of y = 6^(x-9)

Answer 4

yes and then?

Answer 5

i have it

Answer 6

6^x-9 (ln6)

Answer 7

substitute 9 in for x

f'(9) = 6^(9-9)ln(6) = ?

Answer 8

and then?

Answer 9

@mayankdevnani can you help me:)?

Answer 10

now find the equation

y - y1 = m (x - x1)

where m is the answer you got when you substituted 9 into

f'(9) = 6^(9-9)ln(6)

Answer 11

1) http://www.wikihow.com/Find-the-Equation-of-a-Tangent-Line
2) https://www.khanacademy.org/math/differential-calculus/taking-derivatives/product_rule/v/equation-of-a-tangent-line

Answer 12

hope it helps !
@liz_mustang

Answer 13

thank you!:) & okay!

Answer 14

y=8-x?

Answer 15

how did you get that?

Answer 16

it's wrong?

Answer 17

thats my final answer

Answer 18

i think i will jus try again tomorrow, i dont seem to understand it

Answer 19

what dont you understand?

you have (9,1)

you have the original function f(x) = 6^(x-9)

if you substitute 9 in here, you would expect to get 1, which you do.

now you find the derivative, which you did

then substitute 9 into the derivative f'(9) = 6^(9-9)ln(6) =ln(6)

so you just found m

y - 1 = ln(6)(x - 9)

y -1 = ln(6)(x - 9)

y = ln(6)(x-9) + 1

Answer 20

hold on give me asecond to go back

Answer 21

what i did was distribute and simplify at the end.

Answer 22

and i had a 1 instead of a 9 and latter added the 9, i confused x's and y's

Answer 23

lol

Answer 24

i wouldnt distribute ln(6). it would be... messy

Answer 25

any other questions?

Answer 26

I have to go soon, so please ask if you do

Answer 27

yea thats exactly what i did distribute there lol

Answer 28

I will ask tomorrow, Thank you I really appreciate your help!

Answer 29

np, any time

Answer 30

Thank you:)))

Answer 31

:o