anybody know how to do algebraic functions. i struggle with it.
ya shoot
well can you explain how it works please.
well first provide an example cuz you are pretty vague
Do you still need help?
well ok
brb
sure ... *grabs some popcorn*
ok so lets start with linear functions how does that work.
also notations and graphs
Linear functions are in the format of y=mx+b m is the slope b is the y-intercept which is the point on the y-axis where the function intercepts
khan academy lol. my dad always tells me to use that lol and thanks
how about the notations though?
When you graph linear functions the shape of the graph will be a line But depending on the slope thats how steep it will be
Lol your welcome! and hang on I'll find that too
What notations are u looking for y=mx+b is the equation of a liinear function
hmmm ok
well its talking about grapghed noations
ask me a specific question and we can go from there
ok
for example i have to graph this
c = 120 + 5x written using function notation.
anyone there.. @exaplme above
example*
i lost connection...
ok so basic function notation is as follows we refer to a function/equation as f(x) which in real terms is another way of saying y or in this case c c=120+5x We replace the c with f(x) so f(x)=120+5x F(x) just means that the c is dependent on the x So for example when x=1 then c=125 when x=0 then c=120 So as you can see our c depends on the x. We plug in our x value to find what c equals Therefore in general we refer to the answer as f(x) Meaning its a function that is dependent on x so f(1) means find what the function is when x=1. Basically replace x with 1 and solve so f(1)=120+5(1)=125 and f(0)=120+5(0)=120 Do you follow?
yeah i lost connection but im back now
let me read it real quick
lol ya i just posted it .... I wrote a long thing
ok
but just wondering is there a way to graph this?
ya not sure if you followed. Maybe I can find a video that explains this concept better
and yeah ik about the replacing of the 1 and stuff.
yes so basically we replace c with f(x) So f(x)=120+5x And now what we are gonna do is choose a couple of points that we would like to plot Lets choose x =-2,-1,0,1,2 So we are gonna start with x=-2 f(-2)=120+5(-2)=120-10=110 so our first point is at (-2,110) f(-1)=120+5(-1)=120-5=115 so our second point is at (-1,115) f(0)=120+5(0)=120 So our third point is at (0,120) f(1)=120+5(1)=120+5=125 So our fourth point is at (1,125) f(2)=120+5(2)=120+10=130 So our fifth point is at (2.130) So graph these 5 points on a coordintae grid and then a draw a line connecting these points
ok thanks
idk why i keep losing connection
but thanks
lol do you get it??? I can show you how to graph..
for your help.
Ya openstudy kinda sucks :D
Do you follow or you need some more explanation?
no im good
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