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Mathematics
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Part C - Profit Optimization
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@dumbcow I got A and B, how do I do C? :/
can u show ur work for parts a and b quick ?
i think u need to use similar method for solving part c by accounting for the extra cost function
Revenue = Price * Quantity Profit = Revenue - Cost
Revenue: R(x) = -x^2/10 + 550x Cost: C(x) = 60,000 + 140x So P(x) -x^2/10 + 410x - 6000 Derive P(x) to find max x, then plug x into P(x) ?
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\[C(x) = 60,000 + 140x \implies P(x) = R(x) - C(x)\]
What's P'(x)?
410-x^5
Try again
(-1/5)x + 410
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Yeah that looks good
now set that = 0 and solve for p(x) what ever you found for the x value earlier
Then subtract by 450
haha i was too slow
:)
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thanks guys
Np
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