You have been invited to a fancy dinner party celebrating your hard work in Algebra 2 so far. The distinguished guests come from various aspects of math disciplines like professors, engineers, and financial analysts. 1. A mysterious box is delivered to the dinner party you are attending. The label on the box says that the volume of a box is the function f(x) = x3 + 3x2 – 10x – 24. To open the box, you need to identify the correct factors of f(x). Partygoers offer up solutions, and it is your job to find the right ones. Their suggestions are:
• (x – 1) • (x + 2) • (x – 3) • (x + 4) • (x + 6) • (x – 12) List the correct factors. Then justify your selections with complete sentences. 2. Three partygoers are in the corner of the ballroom having an intense argument. You walk over to settle the debate. They are discussing a function g(x). You take out your notepad and jot down their statements. • Professor McCoy: She says that 2 is a zero of g(x) because long division with (x + 2) results in a remainder of 0. • Ms. Guerra: She says that 2 is a zero of g(x) because g(2) = 0. • Mr. Romano: He says that 2 is a zero of g(x) because synthetic division with 2 results in a remainder of 0. Correct the reasoning of any inaccurate reasoning by the partygoers in full and complete sentences. Make sure you reference any theorems that support your justifications. 3. Dr. Collier summons you over to his table. He wants to demonstrate the graph of a fourth-degree polynomial function, but the batteries in his graphing calculator have run out of juice. Explain to Dr. Collier how to create a rough sketch of a graph of a fourth-degree polynomial function. 4. Mrs. Collins is at the table with you and states that the fourth-degree graphs she has seen have 4 real zeros. She asks you if it is possible to create a fourth-degree polynomial with only 2 real zeros. Demonstrate how to do this and explain your steps.
@ParthKohli
@hba
Have you tried plugging in the possible solutions?
i already got x+4 x+2 x-3 @ParthKohli
What's the problem then?
The rest of it, lol
lol
Here's a subtle hint. If you have a polynomial f(x) and dividing it by a polynomial (x - r) gives a zero remainder, then that means r is a zero of the polynomial f(x). What does that say about Professor McCoy's claim?
I'm still stuck on # 1 LOL @Supreme_Kurt
Thought you already got it?
yeah but idk how to justify the selections with complete sentences.
The usual problems :) There are several ways to determine whether a binomial x - r is indeed a factor of a polynomial. For number 1, we may as well stick to the simplest. Each binomial x-r has a root, and it is r. For instance, in the binomial x - 4, its root is 4. For x - 2, its root is 2. Careful, though, for x + 2, the root is -2. Mind your signs. Everything understood?
nvm..
Something wrong?
not my question.
We'll get to that. I'm trying to explain the concept behind it :)
oh okay sorry yes i got that so far :)
but i'm confused on why x+2 root would be -2
Good. So, we'll test out your choices to see if they are indeed, factors of your polynomial. What's the root of x+4 ?
Because in any x - r, the root is r itself. And x + 2 is the same as x - (-2) and so, the root is -2
oh so the root of x+4 is 4
You can also (and should) think of the root as the value of x that would make the polynomial equal to zero. Notice that in x + 2, the value of x that would make x+2 zero is -2. You may want to rethink that.
oh yeaahhhh -4 because x+4 is same as x-(-4)
Yes. Exactly. So, x+4 is a factor of your polynomial x3 + 3x2 – 10x – 24 IF -4 is ALSO a root of this longer polynomial. So... test it out. See if substituting -4 for x in x3 + 3x2 – 10x – 24 results in zero. Try it. I'll wait ^^
-4^3+3(-4)^2-10(-4)-24?
...yes. Go ahead and do the dirty arithmetic work. You can do it :D
Stuck?
thank you! -64-144+40-24
i think i got it @Supreme_Kurt
144 is off. Try figuring out 3(-4)^2 again :)
i got +144
Still no. Remember, you only square the (-4) part, not the 3. ;)
oooh yeaaah 48 sorry
@Supreme_Kurt
Good. Now simplify ^^
I got 0
So that proves that x+4 is, in fact, a factor. Try it with x+3. What's the root of x+3 ?
3^3+3(3)^2-10x-24
sorry -10(3)
27+27-30-24
Is it zero?
and I also got 0 for that yeah
So, that means x+3 is a factor :D
You getting the hang of it yet? :D
yes i am :)
Oops, I meant x - 3 My bad haha
What's the root of x+2?
-2
Good. Now try -2 with your long polynomial, see it gives zero :)
8+12+20-24
no i got 16
Careful... what's (-2)^3 ?
-8 sorry
Good. Try again ;) Be VERY careful with signs. Just one wrong sign can really f**k things up... trust me :)
lol yeh so now i got 0
And that wraps it up :D
so is that how i should explain in complete sentences?
Yes. For instance, x+4 is a factor of the polynomial f(x) because f(-4) is zero. Then show your work. Same for the other factors :D
okay thanks
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