Question

What is the equation of the line that is perpendicular to -x + y = 7 and passes through (-1, -1)?

Answer 1

A. -x + y = 2
B. -x – y = 2
C. x – y = 2
D. -x – y = 0
E. x + y = 0

Answer 2

do u know what is the slope in this equation -x +y =7 ?
if u know then tell me

Answer 3

I don't how do I find it?

Answer 4

first convert the above equation in slope intercept form (y=mx +b )

Answer 5

y = -x + 7?

Answer 6

good
y=mx+b
since, m is slope and b is the y intercept
whereas
y=-x +7
here m=-1
okay your slope is -1
now apply this Perpendicular formula
m x m'=-1
-1 x m'=-1
m'=1

Answer 7

have u got it ?
we apply the perpendicular formula of slope because we require to find out the equation of line which is perpendicular to that equation

Answer 8

So it's D?

Answer 9

no
use this formula
y-y' =m' (x-x')
since
m'=1
(x',y')=(-1.-1)
and put it in the above formula and get the answer

Answer 10

so y - -1 = 1 (x - -1)

Answer 11

yes
y-(-1)=1(x-(-1))
y+1=1(x+1)
y+1=x+1
x-y+1-1=0
x-y=0
this is your equation

Answer 12

x - y = 0 is my equation?

Answer 13

yes
plz again check your choices and point which is given to us in your question from your note book

Answer 14

x + y = 0

Answer 15

yes this is correct answer
do u know where u did mistake
u wrote
y=-x +7 it is in correct
y=x+7

Answer 16

when we take out the slope from it
it would be
m=1
when
m x m'=-1
1 x m' = -1
m'=-1
here
m'=-1
(x',y')=(-1,-1)
apply on these things on this formula and get the correct equation
y-y'=m'(x-x')
y-(-1)= -1(x-(-1))
y+1=-1(x+1)
y+1=-x +1
y+x +1-1=0
x+y =0
x+y=0
this is your correct answer

Answer 17

@CaseyCarns look it here

Answer 18

Thank you so much!

Answer 19

if u have any question u can ask me now?

Answer 20

No I understand!

Answer 21

okay welcome here