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OpenStudy (anonymous):

An observer (O) is located 900 feet from a building (B). The observer notices a helicopter (H) flying at a 49° angle of elevation from his line of sight. What equation and trigonometric function can be used to solve for the height ( h) of the helicopter? Pick another trigonometric function and describe why that function is not appropriate when trying to solve for ( h). You must show all work and calculations.

OpenStudy (anonymous):

OpenStudy (anonymous):

tangent = opp/adj i think, but how to solve it?

OpenStudy (anonymous):

@wio

OpenStudy (anonymous):

We want to use TOA Use TANGENT for ratio of OPPOSITE side divided by the ADJACENT side.

OpenStudy (anonymous):

how? im no good with these:(

OpenStudy (anonymous):

\[ \tan(49^\circ) = \frac{h}{900} \]

OpenStudy (anonymous):

ok then?

OpenStudy (mrnood):

What on earth is this question on! The building seems to be totally irrelevant - it is only useful if the helicopter is known to be exactly above the building, which is not a reasonable assumption. This question requires too many assumptions - the 900 feet is th edistance to the building - not necessarily to the helicopter....

OpenStudy (anonymous):

Then you can say: \[ \sin (49^\circ ) = \frac{h}{\overline{HO}} \]which is not approproate because \(\overline{HO}\) is not given.

OpenStudy (anonymous):

ok

OpenStudy (dan815):

there he goes wio

OpenStudy (dan815):

in its natural habitat

OpenStudy (anonymous):

what was the height?

OpenStudy (anonymous):

lol ikr hes good!

OpenStudy (dan815):

lets move in closer to get a better look at our specimen, watch how he carefully gently pushes the keys down

OpenStudy (mrnood):

You are not asked to find the height , only to say what trig function would enable you to do it (if oyu were given appropriate information)

OpenStudy (dan815):

laTex is in my bones

OpenStudy (anonymous):

actually it does ask me

OpenStudy (dan815):

hahah we lost a wio! you scared him off

OpenStudy (anonymous):

We could say\[ \overline{HO} =\sqrt{h^2+900^2} \]But still \[ \sin(49^\circ) =\frac{h}{\sqrt{h^2+900^2}} \]Is really hard compared to just : \[ \tan(49^\circ) = \frac{h}{900} \]

OpenStudy (mrnood):

What equation and trigonometric function can be used to solve for the height ( h) of the helicopter that is the question - not 'what is th eheight h

OpenStudy (anonymous):

Also they will punish you if you write \(\overline{HO}\) too many times.

OpenStudy (dan815):

hahah

OpenStudy (anonymous):

sorry i posted the wrong uestion

OpenStudy (anonymous):

An observer (O) is located 900 feet from a building (B). The observer notices a helicopter (H) flying at a 49° angle of elevation from his line of sight. What equation and trigonometric function can be used to solve for the height (h) of the helicopter? What is the height of the helicopter? Pick another trigonometric function and describe why that function is not appropriate when trying to solve for (h). You must show all work and calculations to receive full credit.

OpenStudy (dan815):

why do i feel like u havent read the question yet

OpenStudy (mrnood):

So Wio gave you the equation (with tan49 in it) Solve that equation for h

OpenStudy (anonymous):

Does he always do this?

OpenStudy (dan815):

nah heat is a good guy we can trust him

OpenStudy (dan815):

use a calculator heat

OpenStudy (anonymous):

im sorry, i had looked for the question on another openstudy page, and i copied the question from there, turns out it was different

OpenStudy (dan815):

what is tan(49)?

OpenStudy (anonymous):

ok dan

OpenStudy (dan815):

solve the equation!

OpenStudy (dan815):

tan(49)=h/900 ...

OpenStudy (anonymous):

-3.17290855216 = h/900

OpenStudy (dan815):

uhh

OpenStudy (dan815):

use degree mode

OpenStudy (anonymous):

1.15036840722 = h/900

OpenStudy (dan815):

okay better,...

OpenStudy (dan815):

continue

OpenStudy (dan815):

what does h have to be then

OpenStudy (mrnood):

How did you get to be a 'Human Calculator' if you can't do this?

OpenStudy (anonymous):

im no good with these mrnood

OpenStudy (dan815):

hey dont question the mans ability

OpenStudy (anonymous):

h is 1.15036840722

OpenStudy (dan815):

Huh!

OpenStudy (dan815):

no no

OpenStudy (anonymous):

oh lol see i suck xD

OpenStudy (dan815):

1.15036840722 = h/900

OpenStudy (mrnood):

of course I question his abilkity - it is a simple formula with 1 unknown - solve it

OpenStudy (dan815):

HEIGHT OVER 900 = 1 point something

OpenStudy (dan815):

900/900 is 1

OpenStudy (dan815):

so height is greater than 900 if its 1 point something right

OpenStudy (dan815):

multiply both sides by 900

OpenStudy (anonymous):

ohhh

OpenStudy (anonymous):

\[ 1.15\approx \frac{h}{900}\implies 1.5\cdot 900\approx h \]

OpenStudy (anonymous):

h = 1035.3315665

OpenStudy (dan815):

ok better

OpenStudy (dan815):

good job

OpenStudy (dan815):

GOOD JOB HOMIE

OpenStudy (anonymous):

omg sorry i thought it was harder

OpenStudy (anonymous):

now it said pick another trigonometric function and see why its innapropriate when solving for h

OpenStudy (anonymous):

that would be what wio showed me right??

OpenStudy (anonymous):

I explained that before. Reread it.

OpenStudy (anonymous):

ok one sec

OpenStudy (anonymous):

ok got it HO is not given so its inappropriate when finding h

OpenStudy (anonymous):

thanks to the both of ya, uhm can you give each other medals, and who wants mine? xD

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