Question

what is the inverse function of f(x)=x2-4
1) x2+4
2) sqrt(x+4)
3) sqrt(x)+4
4) sqrt(x-4)

Answer 1

f(x)=x^2-4, y=x^2-4, x=y^2-4, x+4=y^2, sqrt(x+4)=y
so the answer is f(x)=sqrt(x+4) HI AGAIn

Answer 2

@Nnesha can you check him

Answer 3

It is \[\sqrt{x+4}\]

Answer 4

yes so we are correct

Answer 5

I hope the teacher gave some restriction to domain
because the inverse isn't actually a function
it is relation since you have y^2=x+4
which implies y=sqrt(x+4) or -sqrt(x+4)

Answer 6

the onkly abswer can be the second

Answer 7

I think you are right, but my teacher never says restrivtions

Answer 8

that's a bit odd

Answer 9

yes it is

Answer 10

@freckles In my online algebra 2 they never mentioned restrictions, but in precalc they do.

Answer 11

@EmmaMink

Answer 12

FLVS criminal idiot s wrote this i bet $20

Answer 13

inverse function of f(x)=x^2-4 doesn't exist
unless they restricted the domain
ex.f(x)=x^2-4 on [0,inf) has inverse g(x)=sqrt(x+4)
ex. f(x)=x^2-4 on (-inf,0] has inverse g(x)=-sqrt(x+4)
if they wanted an inverse relation you could say + or - sqrt(x+4)

Answer 14

I'm a criinal idiot?

Answer 15

they don't know any math, just play a trick on unsuspecting florida students

Answer 16

forget I'm from russia

Answer 17

@ttb123456789 no i am speaking of the FLVS

Answer 18

satellite just really hates the school that makes these questions

Answer 19

because it is not mathematically correct

Answer 20

course i could be wrong

Answer 21

i keep asking for question ID numbers from the wrong questions written by FLVS

Answer 22

so i can bring them to their attention
no one seems to want to provide them

Answer 23

i'm confused

Answer 24

dang ttb123456789 for only 11, you're more advanced than I am in math!