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OpenStudy (anonymous):
OpenStudy (jhannybean):
Test your points, are the same values of y translated on to the other side of the axis?
OpenStudy (jhannybean):
If so, the axis of symmetry that corresponds to the same value will be the one you are looking for.
OpenStudy (jhannybean):
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OpenStudy (jhannybean):
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OpenStudy (anonymous):
So, as long the shape is corresponding (equal) to the other side (x and y axis) that's what I'm looking for exactly?
OpenStudy (jhannybean):
NOt the shape, but the point. in this case specifically, the line of symmetry is the x=0 because points have the same y-value, 1.
OpenStudy (jhannybean):
For quadratic functions, the line of symmetry is found by the vertex \[x=-\frac{b}{2a}\]
OpenStudy (jhannybean):
Let's take for example the function \(y=x^2 +12x+32\), a quadratic function.
OpenStudy (anonymous):
I'm guessing the answer would be 0? If so, not sure what value would it be.
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OpenStudy (anonymous):
@Jhannybean
OpenStudy (jhannybean):
One minute!
OpenStudy (jhannybean):
The answer to your problem would by x=0 since the axis of symmetry for even functions (that is an even function) would be the y-axis, and at the y-axis, x=0