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Mathematics 15 Online
OpenStudy (anonymous):

Quadratic Functions

OpenStudy (anonymous):

OpenStudy (jhannybean):

Test your points, are the same values of y translated on to the other side of the axis?

OpenStudy (jhannybean):

If so, the axis of symmetry that corresponds to the same value will be the one you are looking for.

OpenStudy (jhannybean):

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OpenStudy (jhannybean):

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OpenStudy (anonymous):

So, as long the shape is corresponding (equal) to the other side (x and y axis) that's what I'm looking for exactly?

OpenStudy (jhannybean):

NOt the shape, but the point. in this case specifically, the line of symmetry is the x=0 because points have the same y-value, 1.

OpenStudy (jhannybean):

For quadratic functions, the line of symmetry is found by the vertex \[x=-\frac{b}{2a}\]

OpenStudy (jhannybean):

Let's take for example the function \(y=x^2 +12x+32\), a quadratic function.

OpenStudy (anonymous):

I'm guessing the answer would be 0? If so, not sure what value would it be.

OpenStudy (anonymous):

@Jhannybean

OpenStudy (jhannybean):

One minute!

OpenStudy (jhannybean):

The answer to your problem would by x=0 since the axis of symmetry for even functions (that is an even function) would be the y-axis, and at the y-axis, x=0

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