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If f(x)= 3x-2/2x+1 then f'(x) =
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\[f(x)=\frac{ 3x-2 }{ 2x+1 }\]
Can I use the quotient rule?
Oh wait no because the terms in the numerator and in the denominator aren;t being multiplied
Yes, use quotient rule.
oh no quotient rule for this one for sure
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SATELLIGHT!!!!
oh ok let me try
\[\left(\frac{f}{g}\right)'=\frac{gf'-fg'}{g^2}\]with
whoa SAIFOOOOOOOOOO!
^^
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\[\huge \color{red}{\text{CELERITY IN THE HOUSE!}}\]
Mods these days cx
actually i means celebrity but whatever
Ok I get 7/(2x+1)^2 lol I can't believe I forgot how to do this for a moment ^_^ thanks
\[\left(\frac{f}{g}\right)'=\frac{gf'-fg'}{g^2}\]with \[f(x)=3x-2,f'(x)=3,f(x)=2x+1,g'(x)=2\]
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Celeb = the one with the smartscore of 0.1K. xD
yeah you are right \[\frac{7}{(2x+1)^2}\] does it
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