What is the solution to the system of equations represented by the two equations? y=2/3x y=-2/3x+4
frist add to eq: then we have: y=4 so for find the x you must y=4 into the one of the eq then we have: y=2/3*4= 8/3 so x=8/3
hmmmm
if you use that method, adding them, you actually get \(2y=4\)
the answer is an ordered pair
Just plug in 2/3x for y in the second equation.. \(y = - \dfrac{2}{3}x + 4\) \(\dfrac{2}{3}x = -\dfrac{2}{3}x + 4\) Add 2/3 to both sides. \(\dfrac{4}{3}x = 4\) Now multiply 3/4 to both sides, what's 3/4 * 4? @skeleking518
sorry y=2 then x=4/3
3
In order to find the solution to the system of equations you have to work on the left hand side of the equation first by using "coefficient matrix" and the right hand side with the answer values.
Yes, so the x-value of our solution is 3. Now we can plug in x = 3 into any of the two equations to solve for y. \(y = \dfrac{2}{3}x\) \(y = \dfrac{2}{3}(3)\) Can you multiply 2/3 * 3? @skeleking518
2.6 repeating
No, check again.
3.6 repeating
No..that's wrong.
3.66666666667
No, \(\dfrac{2}{3} \times 3 = 2\)
So our solution is (3, 2).
oh
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