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Mathematics 26 Online
OpenStudy (anonymous):

May I have some help with Algebra II!

OpenStudy (anonymous):

@tkhunny can you help me?

OpenStudy (tkhunny):

Post a problem. Show your work.

OpenStudy (anonymous):

As one of the new roller coaster engineers, you have been tasked with developing a roller coaster that will intertwine with existing Oakville Lake Amusement Park structures. For one of the more thrilling sections, the roller coaster will dive down in-between buildings, plummet underground, pop back up, and coast over a hill before shooting back underground. There must be three distinct points where the roller coaster crosses the x–axis. Precise measurements and attention to detail are very important.

OpenStudy (anonymous):

OpenStudy (anonymous):

1.Using the points above as zeros, construct the polynomial function, f(x), that will be the path of your roller coaster. Show all of your work.: The root 6 has a factor of (x-6), the root -2 has a factor of (x-(-2)), and the root -7 has a factor of (x-(-7)). Multiplying (x-6) and (x+2), I get x^2-4x-12. Then I multiply this by (x+7), so (x^2-4x-12)(x+7). This results in a function of f(x)=x^3 + x^2-28x-12x-84

OpenStudy (anonymous):

I'm stuck on this... Using both fundamental Theorem and Descartes` rule of signs, prove to the construction foreman that your function matches your graph. Use complete sentences.:

OpenStudy (tkhunny):

Not sure where to help you. You seem to have the right idea. Given zeros at -7, -2, and 6, where is the graph when it is right over or under the obstacles? Make sure you have enough clearance.

OpenStudy (anonymous):

I got it actually! Thanks anyways!

OpenStudy (gnrfan):

@Cubi-Cal Im on the same problem how'd you do it?

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