Please check my work before i submit. I'm falling behind with 3 days left. I will fan , award a medal and write a detailed testimonial.
details are always nice what is the question?
this is one of 28 questions i have :(
that would be wrong because you need a minus sign
divide by \(180\) and multiply by \(\pi\) i.e. stick a \(\pi\) next to it
so i have the sign wrong ?
\[-\frac{54}{180}=-\frac{3}{10}\]
Simply just \[-54 \cdot \frac{\pi}{180}\]
i.e reduce, then put a \(\pi\) there get \[-\frac{3\pi}{10}\]
I know `/circ` makes little circles but OS needs to have a fluttering degree symbol.
@satellite73
yeah i haven't figured that out yet \[30^o\] looks ugly
\[-54^\circ\]
\[30^{\circ}\] is not worth the bother
so i see i miss calculated a great deal :(
yes, you did cheat and use a calculator to reduce, it will make your life a lot easier
okay thanks , this is my next answer
You mean your next question?
Im having my answers checked before i submit my work into the system @Jhannybean
think that is a mistake too
the amplitude is 2 for sure, and the period is \(\pi\) but the phase shift i believe no not right
it was explained to me this way i thought it was right :( @satellite73
Fortrig functions: \( F(t) = Af(Bt – C) + D\)
here is the deal there is some formula to use, but i never remember it set \[2x-\pi=0\] solve for \(x\) you get \[2x=\pi\\ x=\frac{\pi}{2}\] so that last one has a phase shift of \(\frac{\pi}{2}\)
so it's just pi when it's simplified
What do you mean by that?
simplifying 2pi /pi would make the phase shift just pi . i believe
the phase pellet of the one you chose is \(\frac{\pi}{4}\) the phase shift of D is \(\frac{\pi}{2}\)
phase pellet?lmao
ohhhh so my answer was backwards ... idk im starting to feel confused
Well first off, why would you think the Amplitude is -2 when they told you it was 2? That would help you eliminate some of your answer choices.
okay i see now . my mistake
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