Question

suppose that a 3 digit number randomly generated using digits from 1-8. Find the probability that the number has at least one repeated digit

Answer 1

if two household are independently selected, what is the probability that both have income in the $30,000- $39,999 range?

Income
0- $9,999 6%
$10,000-$19,999 9%
$20,000- 29,999 13%
$30,000-$39,999 28%
$40,000-$49,999 18%
$50,000-$59,999 17%
$60,000 or more 9%

Answer 2

1-prob of no repeated digits

Answer 3

1-(8*7*6/8^3)

Answer 4

You can count the ways to have at least two repeated digits: 8 ways to have exactly 3 repeated digits (111, 222 etc.) plus 8*7 ways to have only the first two digits repeated (112, 113 etc.) plus 8*7 ways to have only the first and the last digits repeated (121, 131 etc.) plus 8*7 ways to have only the last two digits repeated (211, 311 etc.).

Answer 5

wait i wrote it wrong the number one it will be in total 6 digits (1,2,3,5,7,8) so i did this

6.5.4 / 6.6.6 =120/ 216 i simplify = 5/6 = 0.833

Answer 6

wait if forgot to -1 = 0.167?