Did i did it right?

if two household are independently selected, what is the probability that both have income in the $30,000- $39,999 range?

Income
0- $9,999 6%
$10,000-$19,999 9%
$20,000- 29,999 13%
$30,000-$39,999 28%
$40,000-$49,999 18%
$50,000-$59,999 17%
$60,000 or more 9%

the total of the percentages = 100% - 28% = 72%

and
In an office there are 6 male employees and 7 females employees. suppose two employees are randomly selected to attend a conference. Find the probability that both of the selected employees are male

6/13 x 6/12 = 36/156 i simplify and i get 3/13 = 0.230

Question

Did i did it right?

if two household are independently selected, what is the probability that both have income in the $30,000- $39,999 range?

Income
0- $9,999                6%
$10,000-$19,999    9%
$20,000- 29,999     13%
$30,000-$39,999    28%
$40,000-$49,999    18%
$50,000-$59,999   17%
$60,000 or more       9%

the total of the percentages = 100% - 28% = 72%

and 
 In an office there are 6 male employees and 7 females employees. suppose two employees are randomly selected to attend a conference. Find the probability that both of the selected employees are male

6/13 x 6/12 = 36/156 i simplify and i get 3/13 = 0.230

anonymous · Answer

For the second one its 6C2 / 13C2 = 5/26

anonymous · Answer

First one answer is (28/100)*(28/100) ,what u have calculated is the chance that a particular household selected doesn't have income in the range 30 k t0 39.9 k