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Does the capacitance of a device depend on the applied voltage? What about the charge stored in it?
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No and yes, respectively. The capacitance is an intrinsic property of the device. On the other hand, the stored charge is proportional to the voltage applied \( \left( Q = C\cdot V\right) \).
Can you quickly explain capacitance?
It's defined through the charge equation Q = CV. One way to think about it is that in SI units, a capacitor with a 2 Farad capacitance will store 2 Coulombs of charge for every volt applied across the device.
Okay Thanks so much!! I get it now
No problem.
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