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OpenStudy (anonymous):
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OpenStudy (anonymous):
OpenStudy (abb0t):
All you need to do here is take the sum of each, given by: \(\sf \sum n_i(product) - n_i(reactants)\) where \(\sf n_i\) is the molar coefficient in front of each in the chemical equation!
OpenStudy (anonymous):
I'm gonna need you to literally walk me through this like it's my first day in chemistry
OpenStudy (abb0t):
Ok, start with the products, what do you have and how many? Make a table.
OpenStudy (abb0t):
|dw:1417553325868:dw|
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OpenStudy (abb0t):
|dw:1417553398411:dw|
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