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OpenStudy (anonymous):
whaa
OpenStudy (wwwhhhaaattt?):
@kdog55 TRY
OpenStudy (wwwhhhaaattt?):
Your not trying
OpenStudy (anonymous):
@LexiGirl777 can u help
OpenStudy (wwwhhhaaattt?):
NO ONE ANSWER
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OpenStudy (wwwhhhaaattt?):
DONT HELP
OpenStudy (anonymous):
i am going to answer!
OpenStudy (anonymous):
It's logic. Add two to both sides.
sqrt(x+3) -2 = 2
sqrt(x+3) = 4
Now, what's the only number that, when taken the square root of, gives you 4?
OpenStudy (wwwhhhaaattt?):
DONT ANSWER
OpenStudy (godlovesme):
lol @WWWHHHAAATTT?
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OpenStudy (rainbow_dashie):
1+ x=2
OpenStudy (anonymous):
?????????I'm so confused on what's going on?????????
OpenStudy (wwwhhhaaattt?):
He just wants the answer
OpenStudy (anonymous):
ok and you don't want us to answer it???
OpenStudy (anonymous):
im a GIRL
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OpenStudy (anonymous):
bye i am to confused.sorry @kdog55
OpenStudy (anonymous):
LOL
OpenStudy (godlovesme):
rofl
OpenStudy (anonymous):
@bloopman I got 2
OpenStudy (anonymous):
I'm trying to help you.
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OpenStudy (anonymous):
ME 2 IM LOST BYE
OpenStudy (wwwhhhaaattt?):
Because ive been in 3 questions hes asked but ever time i tryed to tell him to try firsst he said he did but he wouldent show me
OpenStudy (anonymous):
its a girl
OpenStudy (rainbow_dashie):
Hush I'm helping him
@kdog55 3-2= what
OpenStudy (wwwhhhaaattt?):
Rainbow Dont
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OpenStudy (anonymous):
@Rainbow_dashie 1
OpenStudy (anonymous):
No, not when it is squared, but when it is taken the square root of.
OpenStudy (anonymous):
@bloopman i dont understand
OpenStudy (anonymous):
2^2 = 4, but sqrt(?) = 4
OpenStudy (wwwhhhaaattt?):
@kdog55 Try
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OpenStudy (rainbow_dashie):
Okay so x+1+2
OpenStudy (wwwhhhaaattt?):
@Maria195
OpenStudy (anonymous):
@bloopman 16
OpenStudy (anonymous):
@WWWHHHAAATTT? shutup
OpenStudy (wwwhhhaaattt?):
User Disrespect is agianst CoC
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OpenStudy (rainbow_dashie):
K bye I'm not even helping
OpenStudy (anonymous):
Correct, good job.
Back to what we had earlier:
sqrt(x + 3) = 4
Since 16 is the only thing that can betaken the square root of to get 4, that means x + 3 = 16.
So, what is x in the equation x + 3 = 16?
OpenStudy (wwwhhhaaattt?):
Stop helping
OpenStudy (anonymous):
@bloopman is it 13?
OpenStudy (anonymous):
I'll help as I please babe
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OpenStudy (anonymous):
@kdog55, yes. That's your answer x = 13
OpenStudy (anonymous):
thank you , for all your help, can u help wit another one @bloopman
OpenStudy (anonymous):
The strictly algebraic way to do this is like so:
sqrt(x+3) - 2 = 2
sqrt(x+3) = 4
square both sides
x+3 = 16
x = 13
Sure, Ill help with another
OpenStudy (anonymous):
\[10+\sqrt{v-4=6}\] @bloopman
OpenStudy (wwwhhhaaattt?):
If you need help with another
Open a new question
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OpenStudy (anonymous):
nobody is talking to you @WWWHHHAAATTT? , thank u for your NONSERVICE
OpenStudy (anonymous):
@WWWHHHAAATTT? that's not required.
OpenStudy (anonymous):
@kdog55, are you sure you typed that equation correctly? (besides the sqrt going over the equal sign, obviously)
have you learned imaginary numbers?
OpenStudy (anonymous):
Yes im sure
OpenStudy (anonymous):
the sqrt sign is only over the v-4 @bloopman
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OpenStudy (anonymous):
\[10+\sqrt{v-4}=6\] like this
OpenStudy (anonymous):
okay, so
10 +sqrt(v-4) = 6
first things first, subtract 10 from both sides
sqrt(v-4) = -4
now, do u know what we can do from here?
OpenStudy (anonymous):
wait huh,
OpenStudy (anonymous):
10 - 6?
OpenStudy (anonymous):
no, 6 - 10
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OpenStudy (anonymous):
we're isolating the square root
OpenStudy (anonymous):
ok -4
OpenStudy (anonymous):
right, so how do we solve v in
sqrt(v-4) = -4
OpenStudy (anonymous):
add 4 both sides?
OpenStudy (anonymous):
we can't do that, because the 4 in the square root. we have to get it out of the square root
(take your time, don't get frustrated.) i told you implicitly how to do this earlier
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OpenStudy (anonymous):
square both sides ?
OpenStudy (anonymous):
yep. :D
so what do u get for that?
OpenStudy (anonymous):
am i squaring -4? or what
OpenStudy (anonymous):
you're squaring both sides of the equation
OpenStudy (anonymous):
so you will square -4 on the right side
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OpenStudy (anonymous):
idk how to do that, like what numbers
OpenStudy (anonymous):
is it v-4 = -16
OpenStudy (anonymous):
you just square sqrt(v-4) on the left = -4
so (sqrt(v-4))^2 = (-4)^2
OpenStudy (anonymous):
what happens when you square a square root?
OpenStudy (anonymous):
idk i got that and just added -16+4
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OpenStudy (anonymous):
think about it. thw a
OpenStudy (anonymous):
*the square root of 16 is 4. 4^2 = 16. so what does that tell you about (sqrt(x))^2 for any x?
OpenStudy (anonymous):
im totally lost,
OpenStudy (anonymous):
its a perfect square
OpenStudy (anonymous):
alright. so we took the square root of something, then we squared it. now we GOT that original something.
2^2 = 4, sqrt(4) = 2. therefore (sqrt(4))^2 = 4
3^2 = 9, sqrt(9) = 3. therefore sqrt(9))^2 = 9
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OpenStudy (anonymous):
and so on.
so that means the square of a square root is equal to the number inside the square root.
OpenStudy (anonymous):
then whats my answer 16 or 4
OpenStudy (anonymous):
in context, this means (sqrt(v-4))^2 = = v-4. get it?
OpenStudy (anonymous):
we took the square of the square root of v-4 and got v-4
OpenStudy (anonymous):
so v-4 = 16
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OpenStudy (anonymous):
yep! now just solve for v
OpenStudy (anonymous):
16+4?
OpenStudy (anonymous):
mhm.
OpenStudy (anonymous):
20 not the answer
OpenStudy (anonymous):
what are your options?
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