Piecewise function help? Evaluate the piecewise function at the indicated values from the domain: | |x|, if x < = -1 f(x) = { x^2, if -1 <(or equal to) x < 4 at x = -2 | -x, if x >(or equal to) 4 (a.) f(-2) = 2 (b.) f(-2) = -4 (c.) f(-2) = -2 (d.) f(-2) = 4
it is hard for me to read the function and whatever else is there
oh it didn't show that way a sec ago
@freckles I just reformated it
now is the time to show off \(\LaTeX\) skills
so you want to evaluate the function at x=-2 so first of the 3 inequalities that is defined for x which of those sets include x=-2?
is x=-2 in the set x<=1? is x=-2 in the set -1<=x<4? is x=-2 in the set x>=4?
another way to ask that question is to you which inequality is true? -2<=1? -1<=-2<4? -2>=4?
@freckles I typed it in wrong sorry, the first inequality is x < = -1, not positive. -2 works for the first term only
ok when x<=-1 we will use the |x|
\[f(x) \left\{\begin{array}{rcc} |x|& \text{if} & x <-1 \\ x^2& \text{if} & -1\leq x < 4\\ -x& \text{if} & x\geq 4 \end{array} \right. \]
so replace the x in |x| with -2
that equals positive 2, right? what next @freckles
that's it
So the answer is a, f(-2) = 2?
|-2|=2 f(x)=|x| when x<=-1 f(-2)=|-2|=2
@freckles
yes?
so is the answer a, f(-2) = 2?
well I was confirming your answer by saying: |-2|=2 f(x)=|x| when x<=-1 f(-2)=|-2|=2 if it doesn't make sense what I have said, please let me know and please tell me which part but if you need someone to say flat out yes Then okay YES! :)
THANK YOU.
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