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Can someone walk me through this question?
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Suppose you deposit $1500 in a savings account that pays interest at an annual rate of 5%. If no money is added or withdrawn from the account, answer the following questions. How many years will it take for the account to contain $2500? So far I have \[2500 = 1500(1+0.05)^{t}\] \[2500 = 1500(1.05)^{t}\] What next?
@Directrix
holy crap you have a lot of fans
divide by 1500 each side
I help a lot. \[\frac{ 2500 }{ 1500 } = 1.05^{t}\] or \[1.66... = 1.05^{t}\]
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@hartnn Can you help me?
then you can take log on both sides
How do I do that?
\(\Large \log 1.66 = t \log 1.05\) \(\Large t= \dfrac{\log 1.66}{\log 1.05} = ..\)
\[t=10.3877002875\]
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\[t = 10.4 years\]
yes, thats correct :)
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