Question

Help with right triangles?

Answer 1

I feel like I have to be doing this wrong, because my hypotenuse comes out shorter than the longer leg,

Answer 2

can you show me what you did?

Answer 3

One moment please.

Answer 4

I wound up confusing myself and it makes no sense but:

Answer 5

Given the short leg, you need to find the long leg, which means it is not the hypotenuse.
I'm going to guess it is the 30-60-90 triangle given the problem SL=6 and you need to find the LL.
First off, identify the short length, if you look at my diagram, short length is L on the right of my two triangles.
So that means if SL=6 and SL=L, therefore L=6.
To find the LL=\[L \sqrt{3}\]=\[6\sqrt{3}\]

Answer 6

your hypotenuse should be longer because it is = 2L which means it is = 2(6) = 12

Answer 7

sqrt 3 is roughly 1.73

Answer 8

Wow, I feel stupid. That was so easy, Thank you. How would I go about doing problem b?

Answer 9

am i suppose to see a problem b?

Answer 10

if thats your handwriting its very pretty btw @@ i tend to chicken scratch

Answer 11

Thank you! And I meant problem b of the first item I attached. I'll re-attach it:

Answer 12

Oh okay, right.
so if you look at my photo on the left triangle, let's pretend L=6 again.
The two legs will always be the same so both L=6.
Then you have the hypotenuse.
= \[L \sqrt{2}\]
= \[6 \sqrt{2}\]

Answer 13

Are you talking about 30-60-90 or 45-45-90?

Answer 14

sorry 45-45-9

Answer 15

oh wait there were problems at the bottom that I ignored, whoops

Answer 16

okay so 30-60-90 b
if LL=30
\[LL=x \sqrt{3}=30\]
\[x=30/\sqrt{3}\] = regular L

hypotenuse = 2x
you found x from above plug it in and you can find 2x

Answer 17

Is it x = 10, so short leg is 10, long leg is \[10\sqrt{3}\] and hyp is 20?

Answer 18

no the long leg was 30 which was x*sqrt3
and short leg is x so you find x by dividing 30 by sqrt of 3
to find hypotenuse multiply your answer of 30sqrt3 by 2
so it is 50*sqrt3
(no calculator on me)

Answer 19

Okay, thanks.